10y^2=28y-16

Solution for 10y^2=28y-16 equation:

10y^2=28y-16

We move all terms to the left:

10y^2-(28y-16)=0

We get rid of parentheses

10y^2-28y+16=0

a = 10; b = -28; c = +16;
Δ = b2-4ac
Δ = -282-4·10·16
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-12}{2*10}=\frac{16}{20}
=4/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+12}{2*10}=\frac{40}{20}
=2
$